SOLUTION: 200 ice cream cones were sold in one day. Double scoop sold for $1.25 each, single scoops for $1 each. If the proceeds from the sale of cones were $221.75, how many of each kind of

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: 200 ice cream cones were sold in one day. Double scoop sold for $1.25 each, single scoops for $1 each. If the proceeds from the sale of cones were $221.75, how many of each kind of      Log On

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Question 1126421: 200 ice cream cones were sold in one day. Double scoop sold for $1.25 each, single scoops for $1 each. If the proceeds from the sale of cones were $221.75, how many of each kind of cone were sold? In all, how many scoops of ice cream were sold?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
x single scoop
y double scoop

system%28x%2By=200%2Cx%2B1.25y=221.75%29

Try subtracting first equation from second equation to eliminate x and quickly find y.

.

Once you have x and y, the number of CONES for each scoop size, you can find the total number of scoops.

Answer by greenestamps(13206) About Me  (Show Source):
You can put this solution on YOUR website!


The algebraic solution method shown by the other tutor is fine.

Here is a method for finding the solution with less work than the formal algebra, using logical reasoning and a bit of mental arithmetic.

If all 200 cones were single scoops, the total sales would be $200; but it is $21.75 more than that.

The difference between the price of a single scoop and a double scoop is $0.25; the number of double scoop cones required to make that additional $21.75 is

21.75%2F.25+=+87

So....

ANSWERS:

There were 87 double scoop cones sold and 200-87 = 113 single scoop cones.

The total number of scoops sold was 200+87 = 287.