SOLUTION: There were 750 shirts in a box. 1/5 of them were pink and 1/10 were green. The remaining shirts were either yellow or black. If they were 85 more black shirts then yellow shirts, w

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Question 1122090: There were 750 shirts in a box. 1/5 of them were pink and 1/10 were green. The remaining shirts were either yellow or black. If they were 85 more black shirts then yellow shirts, what was the total number of black and green shirts in the box?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
The number of either yellow or black shirts is equal to


    750+-+%281%2F5%29%2A750+-+%281%2F10%29%2A750 = 525.


Now, from the condition, you have these two equations


B + Y = 525,    (1)     (where B = #of black shirts;  Y = #of yellow shirts)

B - Y =  85     (2)


Add these two equations to get


2B = 525 + 85 = 610  ====>  B = 610/2 = 305.


Then from eq(1),  Y = 525 - 305 = 220.


Answer.  305 black shirts and  220 yellow shirts.


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

There were 750 shirts in a box. 1/5 of them were pink and 1/10 were green. The remaining shirts were either yellow or black. If they were 85 more black shirts then yellow shirts, what was the total number of black and green shirts in the box?
As number of black is 305, number of black and green =