SOLUTION: Find the standard form of the equation of the hyperbola with vertices at (2,0) and (6,0) and foci at (0,0) and (8,0).

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Question 1087980: Find the standard form of the equation of the hyperbola with vertices at (2,0) and (6,0) and foci at (0,0) and (8,0).
Answer by ikleyn(53763) About Me  (Show Source):
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The length of the real axis of the hyperbola is 6 - 2 = 4,
and the real axis is the horizontal line y = 0 coinciding with x-axis.


The real semi-axis length is a = 4%2F2 = 2.


The center of the hyperbola is the midpoint between (0,0) and (8,0).
So, the center is the point (4,0).


The foci distance is 8 - 0 = 8.
The half of the foci distance is 8%2F2 = 4.
It is the distance from the hyperbola center to the focus point, which is traditionally called "c".


The imaginary semi-axis "b" is  b%5E2 = c%5E2+-+a%5E2 = 4%5E2+-+2%5E2 = 12.
Hence, b = sqrt%2812%29.


Thus the hyperbola standard form equation is

%28x-4%29%5E2%2Fa%5E2 - %28y-0%29%5E2%2F%28sqrt%2812%29%29%5E2 = 1,


or, which is the same,  

%28x-4%29%5E2%2F4 - y%5E2%2F12 = 1.





Hyperbola %28x-4%29%5E2%2F4 - y%5E2%2F12 = 1  


The foci are (0,0) and (8,0).

See the lessons
    - Hyperbola definition, canonical equation, characteristic points and elements

    - Standard equation of a hyperbola
    - Identify elements of hyperbola given by its standard equation
    - Find the standard equation of a hyperbola given by its elements

    - General equation of a hyperbola
    - Transform general equation of a hyperbola to the standard form by completing the square
    - Identify elements of a hyperbola given by its general equation

    - OVERVIEW of lessons on hyperbolas
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Conic sections: Hyperbolas. Definition, major elements and properties. Solved problems".