SOLUTION: Milk that has 3.25% milkfat is mixed with milk that has 1% milkfat. What volume of each is needed to obtain 60 litres of milk that has 3% milkfat? Express answer to the nearest ten

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Question 1080287: Milk that has 3.25% milkfat is mixed with milk that has 1% milkfat. What volume of each is needed to obtain 60 litres of milk that has 3% milkfat? Express answer to the nearest tenth of a litre.
Note: Please include a "Let's statement(s)", and equations. Thank you :)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website!
Not exactly the same, but a helpful example of the same kind:
using just one variable for a two-part mixture - example

Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!

Milk that has 3.25% milkfat is mixed with milk that has 1% milkfat. What volume of each is needed to obtain 60 litres of milk that has 3% milkfat? Express answer to the nearest tenth of a litre.
Note: Please include a "Let's statement(s)", and equations. Thank you :)

Let amount of 3.25% milkfat to be added, be T
Then amount of 1% milkfat to be added = 60 - T
We then get the following MIXTURE equation: .0325T + .01(60 - T) = .03(60)
.0325T + .6 - .01T = 1.8
.0325T - .01T = 1.8 - .6
.0225T = 1.2
T, or amount of 3.25% milkfat to be added =
Amount of 1% milkfat to be added:
If you want a system of equations, then let the amount of 3.25% and 1% to be added, be T, and S, respectively
Then the system is:
Solve for T, and S to get the amount of 3.25% and 1%, respectively.
It's that easy. Nothing COMPLEX nor CONFUSING!