SOLUTION: Amy, Shen, and Ryan have a total of $68 in their wallets. Shen has $8 more than Amy. Ryan has 2 times what Shen has. How much do they have in their wallets?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Amy, Shen, and Ryan have a total of $68 in their wallets. Shen has $8 more than Amy. Ryan has 2 times what Shen has. How much do they have in their wallets?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1079284: Amy, Shen, and Ryan have a total of $68 in their wallets. Shen has $8 more than Amy. Ryan has 2 times what Shen has. How much do they have in their wallets?
Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let A = "How much Amy has in his wallet".

Then Shen has A+8 dollars, Ryan has 2*(A+8), according to the condition.

In total, they have 68 dollars, which gives you an equation

A + (A+8) + 2*(A+8) = 68.

Simplify it:

A + A + 8 + 2A + 16 = 68,

4A = 68 - 16 - 8,

4A = 44.


Can you complete from this point on your own ?