SOLUTION: The number of wolves in the wild is decreasing at the rate of 3.5% per year. The community has counted 80 wolves in the area. After how many years will this population of 80 wolves

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Question 1052120: The number of wolves in the wild is decreasing at the rate of 3.5% per year. The community has counted 80 wolves in the area. After how many years will this population of 80 wolves drop below 15 wolves, if this rate of decrease continues?
Found 2 solutions by jorel555, advanced_Learner:
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
If the number of wolves is declining at 3.5% per year, then each successive year has 96.5% of the wolves from the year before. So:
80(.965^n)=15, where n is the number of years from the original count
15/80=.965^n
.1875=.965^n
n=approximately 48 years before the wolf population drops below 15 at the stated rate. ☺☺☺☺

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
The number of wolves in the wild is decreasing at the rate of 3.5% per year. The community has counted 80 wolves in the area. After how many years will this population of 80 wolves drop below 15 wolves, if this rate of decrease continues?
the formation is
%28new+amount%29=%28initial+amount%29*%281-%28r%2F100%29%29%5Et
%2815%29=80*%28.965%29%5Et
%280.1875%29=%28.965%29%5Et
ln%280.1875%29=t*ln%28.965%29

-1.67397643357=t*%28-0.03562717764%29
%28-1.67397643357%29%2F%28-0.03562717764%29=t
t=47 Years approximately.