SOLUTION: Jack and Sangeeta are facing each other on opposite sides of a 10-m flagpole. From Jack's point of view, the top of the flagpole is at an angle of elevation of 50 degrees. From San

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Jack and Sangeeta are facing each other on opposite sides of a 10-m flagpole. From Jack's point of view, the top of the flagpole is at an angle of elevation of 50 degrees. From San      Log On

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Question 1044492: Jack and Sangeeta are facing each other on opposite sides of a 10-m flagpole. From Jack's point of view, the top of the flagpole is at an angle of elevation of 50 degrees. From Sangita's, it is 35 degrees. How far apart are Jack and Sangita?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let Jack's distance from the pole = +a+
Let Sangeeta's distance from the pole = +b+
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Jack's equation:
(1) +tan%28+50+%29+=+10+%2F+a+
Sangeeta's equation:
(2) +tan%28+35+%29+=+10+%2F+b+
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(1) +a+=+10%2Ftan%2850%29+
(1) +a+=+10%2F1.1918+
(1) +a+=+8.391+ m
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(2) +b+=+10%2Ftan%2835%29+
(2) +b+=+10%2F.7002+
(2) +b+=+14.281+ m
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Their distance apart is:
+a+%2B+b+=+8.391+%2B+14.281+
+a+%2B+b+=+22.672+
They are 22.672 meters apart
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Check my math!