Question 1012130: A bag of candy contains 3 blue,5 red,4 green, and 3 brown pieces.
What is the probability of picking a blue and then a green, with replacements?
What is the probability of picking a blue and then a green, without replacement?
The probability of choosing a blue,putting it back and picking another candy is 1/15. What was the second color picked
You have a new bag of 20 pieces of candy with the same colors of candy, just different amounts. You know they are 5 reds. You pick a red, don't put it back and then pick a green. The probability of this happening is 3/38. How many greens are there
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! P(b) then (g) with=(3/15)(4/15)=12/225
P(b) then (g) without=(3/15)*4(14)=2/35
(3/15)(x/12)=1/15
x=4, so it must be green.
(5/20)(x/19)=5x/380
3/38=30/380
Therefore, 5x=30, x=6
There are 6 greens
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