SOLUTION: the mass of the mixture A of the beans and maize is 72kg. the ratio of beans to maize is 3:5 respectively.
a)find the mass of the maize in the mixture.
b)a second mixture B of
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-> SOLUTION: the mass of the mixture A of the beans and maize is 72kg. the ratio of beans to maize is 3:5 respectively.
a)find the mass of the maize in the mixture.
b)a second mixture B of
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Question 1101806: the mass of the mixture A of the beans and maize is 72kg. the ratio of beans to maize is 3:5 respectively.
a)find the mass of the maize in the mixture.
b)a second mixture B of beans and maize of mass 98kg is mixed with A . the final ratio of beans to maize is 8 : 9 respectively. find the ratio of beans to maize in B ? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! a)Let n be the common factor in the ratio 3:5. Then:
3n+5n=72
8n=72
n=9
3n=27 kg beans
5n=45 kg maize
b)98+72=170
8n+9n=170
n=10
Final mixture:
80 kgs beans
90 kgs maize
80-27=53
90-45=45
The ratio of mixture B is 53:45
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