SOLUTION: How many solutions does a quadratic usually have?
Find the missing value that makes the trinomial a perfect square
x^2+20x+____ & x^2-3/4x+____
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-> SOLUTION: How many solutions does a quadratic usually have?
Find the missing value that makes the trinomial a perfect square
x^2+20x+____ & x^2-3/4x+____
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Question 33426: How many solutions does a quadratic usually have?
Find the missing value that makes the trinomial a perfect square
x^2+20x+____ & x^2-3/4x+____ Found 2 solutions by stanbon, sarah_adam:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1st: Divide the 20 by 2 and square the result to get 100
x^2+20x+100 is a perfect square.
2nd: Divide the (-3/4) by 2 to get (-3/8) then square to get 9/64
x^2-(3/4)x+(9/64) is a perfect square.
Cheers,
Stan H.
You can put this solution on YOUR website! Every quadratic equation has at most two solutions, but for some equations, the two solutions are the same number, and for others, there is no solution on the number line (because it would involve the square root of a negative number).
x^2+20x+____
In order to be a perfect square the equation should be
But we know = +2*a*b+
so comparing the equation with the standard form lets replace the values of
a = x ;2*a*b = 20x ;we need to find b
2*a*b = 20x
b = 20x/2x = 10
so now we have a =1x; b = 10
= +2(1x)(10)+
SO here the missing terms is 100
x^2-3/4x+____
Applying the above procedure try to solve the second one except instead of using use = -2*a*b+
you should get the value as 9/64
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