SOLUTION: Tickets for the school play sell for $3 for a student and $5 for an adult. one night, 595 people bought tickets. the school took in $1951. How many adult tickets and how many stude

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Tickets for the school play sell for $3 for a student and $5 for an adult. one night, 595 people bought tickets. the school took in $1951. How many adult tickets and how many stude      Log On


   



Question 825616: Tickets for the school play sell for $3 for a student and $5 for an adult. one night, 595 people bought tickets. the school took in $1951. How many adult tickets and how many student tickets were sold?
I did so far: 3s+5A=595

Answer by Fermat(136) About Me  (Show Source):
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Let s be the number of students.
Let a be the number of adults.
Total number of people = s + a = 595.
Tickets for students are $3/student, so revenue from students = 3s dollars.
Tickets for adults are $5/adult, so revenue from adults = 5a dollars.
Total revenue = 3s + 5a = 1951.
Our two equations then are,
s + a = 595
3s + 5a = 1951
multiplying the 1st eqn by 3,
3s + 3a = 1785
3s + 5a = 1951
subtracting the 1st eqn from the 2nd eqn,
2a = 266
a = 133
s = 595 - 133 = 462
Number of adult tickets sold = 133
Number of student tickets sold = 466