Question 763755: One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much.
Answer by MathTherapy(10555)   (Show Source):
You can put this solution on YOUR website!
One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much.
Let the smaller, or first number be S
Then larger or second number = S + 1
Therefore, 2(S + 1) = 4S - 20
2S + 2 = 4S - 20
2S - 4S = - 20 - 2
- 2S = - 22
S, or smaller/first number =  , or 
Larger/second number = S + 1, or 
You can do the check!!
Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
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