Question 682064: Need help putting this world problem into a linear equation:
There are three types of phones in a shipment: Android, Blackberry, and
iphone. The shipment has the following specifications:
- The total number of phones is 195.
- The total value is $88225.
- The number of iphones equals twice the number of Android phones and
twice the number of Blackberry phones combined.
- The value of each phone is $195 for an Android, $150 for a Blackberry,
and $595 for an iphone
Found 2 solutions by JBarnum, mananth: Answer by JBarnum(2146) (Show Source): Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Android,...........x
Blackberry,........y
and iphone.--------z
The total number of phones is 195.
x+y+z=195..................(1)
- The total value is $88225. The value of each phone is $195 for an Android, $150 for a Blackberry,
and $595 for an iphone
195x+150y+595z=88225.............(2)
- The number of iphones equals twice the number of Android phones and
twice the number of Blackberry phones combined.
z=2x+2y
2x+2y-z=0.....................(3)
solve for x y & z
You will get 25, 40,130 phones respectively.
m.ananth@hotmail.com
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