Question 681907: The total of three numbers is 118. The second one is seventeen less that the first one;the third one is five more than three times the first one. Form an equation and solve it to find the three numbers.
Answer by tsewaitung(11)   (Show Source):
You can put this solution on YOUR website! let the first number be x,the second number be y, and the third number be z.
from the question, we have
x+y+z=118
y=x-17
z=3x+5
by substituting the second and the third equation into the first equation, we have
x+(x-17)+(3x+5)=118
x+x-17+3x+5=118
5x-12=118
5x=130
by substituting x=26 into the second equation, we have
y=(26)-17
by substituting x=26 into the third equation, we have
z=3(26)+5
z=78+5
checking:
by substituting x=26, y=9, and z=83 into the first equation, we have
(26)+(9)+(83)
=118
the three numbers are 26,9,and 83.
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