Question 55258: If the number of students majoring in computer scince at York College was 180 in 2002 and 210 in 2005 and if this number increases linearly each year, what will be the approximate number of students majoring in computer scince at york college
a) in the year 2008?
(hint: let the x-coordinate of each point represent the year and the y-cordinate represent the computer schince enrolment)
b)in the year 2012?
Found 2 solutions by tutorcecilia, funmath:
Answer by tutorcecilia(2152)   (Show Source):
You can put this solution on YOUR website! y=mx+b [Use the slope-intercept form of a line since this is a linear problem. That is, the enrollment increases linearly with each passing year. The year is the independent variable (x) and the enrollment is dependent upon the time, so enrollment is the dependent variable (y)]
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(2002, 180)=(2, 180) [Let year 2002 = x=2]
(2005, 210) [Let year 2005 = y=5]
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m=(y-y2)/(x-x2) [Use the formula for a slope]
m= (210-180)/(5-2) [Plug-in the values]
m=(210-180)/(5-2)=30/3=10
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y-mx+b [Use the slope-intercept form of a line]
180=(10)(2) +b [Plug-in the values for one point and the slope]
180=20+b [solve for b]
160=b [The y-intercept]
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y=10x+160 [Slope-intercept equation of the line]
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What will be the approximate number of students majoring in computer since at york college:
a) in the year 2008? [Let 2008=x=8]
(2008, y) = (8, y)
y=(10)(8)+160 [solve for y]
y=240
So, in year 2008, the enrollment should be 240 students.
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b)in the year 2012?
Let 2001=year #1
Use the y=mx+b form of a line and plug-in the values.
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Answer by funmath(2933)  (Show Source):
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