Question 478031: This week in class we are dealing with negative exponents and solving radical expressions. These are commonly used in many different formulas.
Part a: Solve for x:
a=bx^(-2)
Part B:
Given the following information, solve for b: a = 1000, x = 2325
Also: a = 1000, x = 245
2.
The Pythagorean Theorem is a^2+b^2=c^2.
Solve the equation for b.
Part 2: If c = 225, and a = 121, solve for b.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Part a: Solve for x:
a=bx^(-2)
Multiply thru by x^2 to get:
ax^2 = b
x^2 = b/a
x = +/-sqrt[b/a]
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Part B:
Given the following information, solve for b: a = 1000, x = 2325
b = ax^2
b = 1000*2325^2
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Also: a = 1000, x = 245
b = 1000*245^2
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2.
The Pythagorean Theorem is a^2+b^2=c^2.
Solve the equation for b.
b^2 = (c^2-a^2)
b = +/-sqrt(c^2-a^2)
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Part 2: If c = 225, and a = 121, solve for b.
Solutions:
b = +/-sqrt(225^2-121^2)
b = +/-189.6945
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Cheers,
Stan H.
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