SOLUTION: the amount of radioactive tracer remaining after t days is given by A=Aoe^(-0.058t), where Ao is the starting amount at the begining of the time period. How many days will it tak

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the amount of radioactive tracer remaining after t days is given by A=Aoe^(-0.058t), where Ao is the starting amount at the begining of the time period. How many days will it tak      Log On


   

Question 46758: the amount of radioactive tracer remaining after t days is given by
A=Aoe^(-0.058t), where Ao is the starting amount at the begining of the time period. How many days will it take for one half of the original amount to decay.
Answer by adamchapman(301) About Me  (Show Source):
You can put this solution on YOUR website!
A=A%5B0%5D+e%5E-0.058t
A=A%5B0%5D%2F2
So:
A%5B0%5D%2F2=A%5B0%5D+e%5E-0.058t
Dividing by A%5B0%5D:
1%2F2=e%5E-0.058t
ln%280.5%29=-0.058t
t=-ln%280.5%29%2F0.058
t=11.9508 days.

I hope this helps,
Adam
P.S. please visit my website, it may be helpful to you. The address is www.geocities.com/quibowibbler