SOLUTION: 10) A plane flew 1000 miles with a tailwind in 2 hours. the return trip against the wind took 2 1/2 hours. Find the speed of the wind and the speed of the plane in still air.
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Question 42788This question is from textbook Intermediate Algebra
: 10) A plane flew 1000 miles with a tailwind in 2 hours. the return trip against the wind took 2 1/2 hours. Find the speed of the wind and the speed of the plane in still air.
I have the equations y-x(210)=1000 and x+y(150)=1000 is that correct and how will I solve.
12) Sue miller had to move some supplies. She rented a Portland Rent-A-Truck in April for 5 days and drove 150 miles. She paid $180 for the rental in April.In May she rented again for 7 days and drove 320 miles. She paid $274 for the rental in MAy. How much does Portland rent-a-truck charge daily and how much do they charge a mile? This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! WIND SPEED =W PLANE SPEED IN STILL AIR =P
SPEED IN TAIL WIND =P+W .SPEED IN HEAD WIND =P-W D=1000
TIME FOR TRAVEL IN TAIL WIND =1000/(P+W)=2 ..OR P+W=500 ..I
TIME FOR TRAVEL IN HEAD WIND =1000/(P-W)=2.5 ..OR P-W=400 ..II
EQN.I+EQN.II .2P=900 ..P=450
HENCE W =50
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LET RENT/DAY=D .AND ..RATE PER MILE =M
CHARGE FOR 5 DAYS =5D .CHARGE OR 150 MILES =150M .TOTAL = 5D+150M=180 .OR .D+30M=36 .I
CHARGE FOR 7 DAYS =7D .CHARGE OR 320 MILES =320M .TOTAL = 7D+320M=274 .. .II
EQN.II-7*EQN.I 7D+320M-7D-210M=274-252=22 ..110M=22 ..M=0.2 $/MILE
D=36-30*0.2=36-6=30 $/DAY
