Question 148583: for each line discrbed find an equation of the line in slope intercept form and in standard form.
through (4,-2)and perpendiculap to the line (3,7) and (5,6)
Answer by mangopeeler07(462)   (Show Source):
You can put this solution on YOUR website! through (4,-2):
y=mx+b becomes
-2=m4+b
perpendicular to the line (3,7) and (5,6):
Find the slope of the goes that goes through (3,7) and (5,6) by putting the difference of the y's over the differences of the x's
7-6/3-5
Simplify that and get
1/-2
Now flip it
-2/1
Now multiply it by -1
2/1
This is the slope you want for the equation. Plug it in
y=mx+b becomes
-2=m4+b becomes
-2=2(4)+b
Now solve for b. First simplify 2(4)
-2=8+b
Now subtract 8 from both sides
-10=b
Now set the equation up without the x and y coordinates:
y=mx+b becomes
y=2x-10----------------this is your answer in slope intercept form
To change it to standard form, move the x over to the other side.
y-2x=-10
or -2x+y=10
Slope-intercept: y=2x-10
Standard: -2x+y=10
Graph:
| Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc |
Equation  describes a sloping line. For any
equation ax+by+c = 0, slope is  .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -10/-2 = 5.
- Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -10/1 = -10.
- Slope is --2/1 = 2.
- Equation in slope-intercept form: y=2*x+-10.
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