Question 1163722: Bob and Moe set off at the same time on a 30 km walk for charity. Bob walks 1.4 km/h faster than Moe, but stops for 20 min on route. Even with the delay, Bob finishes 2 hours ahead of Moe. How fast in km/h was Bob walking, and how long in hours did it take for Moe to finish the walk?
Found 2 solutions by ikleyn, Edwin McCravy: Answer by ikleyn(52786) (Show Source):
You can put this solution on YOUR website! .
Bob and Moe set off at the same time on a 30 km walk for charity. Bob walks 1.4 km/h faster than Moe, but stops for 20 min on route.
Even with the delay, Bob finishes 2 hours ahead of Moe.
How fast in km/h was Bob walking, and how long in hours did it take for Moe to finish the walk?
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Let x be the Bob's rate, in km/h (the value under the problem's question).
Then Moe's rate is (x-1.4) km/h, according to the condition.
Bob's time walking is hours (with no counting the time for stop).
Moe's time walking is hours.
The time equation for their trips is
Moe's time - Bob's time = 2 hours,
Or in the Math form,
- ( ) = 2.
Here represets Bob's 20 minute stop.
So, your final setup "time equation" is
- = .
in the right side is 2 + .
I will leave the solution of this equation to you, because the rest is just a technique.
Your next steps are
1) multiply both sides by 3x*(x-1.4);
2) then reduce it to the standard quadratic equation
3) then solve it via the quadratic formula or factoring (whichever methods works and whichever you prefer).
At this point, I complete my instructions.
The rest is on you.
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To see many other similar solved problems amd/or to learn more about time equation, look into the lessons
- Had a car move faster it would arrive sooner
- How far do you live from school?
- Earthquake waves
- Time equation: HOW TO use, HOW TO write and HOW TO solve it
in this site.
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Answer by Edwin McCravy(20056) (Show Source):
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