Question 1163440: Divide 56 into two parts such that three times the first part exceeds one third of the second by 48. The parts are
Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website!
From the given information, you can formulate two equations
x+y = 56
3x = (1/3)y + 48
These can be solved for x=20, y=36
This is also a great problem to try to solve in your head, without using pencil and paper.
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