Question 1029847: Can't figure out how to set this problem up correctly
Doreen and Irena plan to leave their houses at the same time, roller blade towards each other, and meet for lunch after 4 hours on the road.
Doreen can maintain a speed of 9.9 miles per hour, which is 90% of Irena's speed.
If they meet exactly as planned, what is the distance between their houses?
Found 2 solutions by fractalier, mananth:
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! Okay, one way to find the total distance between them is to look at how much distance each girl travels and add them together...remember that distance = rate times time...
For Doreen, she covers a distance of (9.9)(4) = 39.6 miles.
For Irena, her speed is 11 miles per hour (found in a separate calculation, Doreen = 9.9 = .9(Irena)), so that
Irena covers (11)(4) = 44 miles
Thus the total distance between them is
39.6 + 44 = 83.6 miles.
Answer by mananth(16946)  (Show Source):
You can put this solution on YOUR website!
Doreen and Irena plan to leave their houses at the same time, roller blade towards each other, and meet for lunch after 4 hours on the road.
Doreen can maintain a speed of 9.9 miles per hour,
which is 90% of Irena's speed.
Irena,s speed will be 9.9*100/90
Irena's speed = 11 mph
Let the distance between their houses be x
t=d/r
they are moving towards each other.
their rate together will be 11+9.9 = 20.9 mph
t=4
4 = x/20.9
x= 83.6 miles
the distance between their houses is 83.6 miles
If they meet exactly as planned, what is the distance between their houses?
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