SOLUTION: Solve 4^(2x) = 7^(x−1). It's a logarithmic problem

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Question 982834: Solve 4^(2x) = 7^(x−1).
It's a logarithmic problem
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve 4^(2x) = 7^(x-1).
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2x*log(4) = (x-1)*log(7) = x*log(7) - log(7)
2x*log(4) - x*log(7) = - log(7)
x*log(16) - x*log(7) = - log(7)
x%2A%28log%287%29+-+log%2816%29%29+=+log%287%29
x*log(7/16) = log(7)
x+=+log%287%29%2Flog%287%2F16%29