SOLUTION: I've tried to solve these linear equations -5x+3y=-5 y=5/3x+1 ...About five times but I keep getting 3=-5. Please explain to me what I am doing wrong and how I can correct my

Algebra ->  College  -> Linear Algebra -> SOLUTION: I've tried to solve these linear equations -5x+3y=-5 y=5/3x+1 ...About five times but I keep getting 3=-5. Please explain to me what I am doing wrong and how I can correct my       Log On


   



Question 794210: I've tried to solve these linear equations
-5x+3y=-5
y=5/3x+1
...About five times but I keep getting 3=-5. Please explain to me what I am doing wrong and how I can correct my error. I'm supposed to find the Point of Intersect without graphing or calculators.

Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I've tried to solve these linear equations
-5x+3y=-5
y=5/3x+1
...About five times but I keep getting 3=-5.
-------------
Put the 1st one in slope-intercept form
-5x+3y=-5
3y = 5x - 5
y = (5/3)x - 5/3
----
Both slopes are 5/3 --> parallel lines, no intersection, inconsistent system.
No solution.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

-5x%2B3y=-5......eq.1
y=%285%2F3%29x%2B1......eq.2
___________________________substitute y from eq.2 in eq.1
-5x%2B3%28%285%2F3%29x%2B1%29=-5......eq.1....solve for x
-5x%2B3%285%2F3%29x%2B3=-5
-5x%2Bcross%283%29%285%2Fcross%283%29%29x%2B3=-5
-5x%2B5x%2B3=-5
-cross%285x%29%2Bcross%285x%29%2B3=-5
+3=-5.......no solution exist, lines have no intersection point
if you write both eq. in slope-intercept form y=mx%2Bb where m=slope and b=y-intercept, you will have
+y=%285%2F3%29x-5%2F3......eq.1
y=%285%2F3%29x%2B1......eq.2
as you can see, slopes are same, both lines have m=%285%2F3%29 and it means lines are parallel
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%285%2F3%29x-5%2F3%2C+%285%2F3%29x%2B1%29+