SOLUTION: For x²(a-b)+a²(b-x)+b²(x-a) show that (x-a) is a linear factor. PLEASE HELP ME!!!!!!

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Question 166514: For x²(a-b)+a²(b-x)+b²(x-a) show that (x-a) is a linear factor.
PLEASE HELP ME!!!!!!

Found 2 solutions by Edwin McCravy, ptaylor:
Answer by Edwin McCravy(20081) About Me  (Show Source):
You can put this solution on YOUR website!
For x%5E2%28a-b%29%2Ba%5E2%28b-x%29%2Bb%5E2%28x-a%29 show that %28x-a%29 is a linear factor.

We use the fact that if a number is substituted for x 
in a polynomial, the result is the same as the remainder 
left when that polynomial is divided by x minus that number.

So we substitute x=a in the polynomial to see if the
remainder is 0, and if it is then we'll know that if we 
had divided the polynomial by x-a, the reaminder
would be 0, making x-a a factor:

So we substitute x=a into the polynomial:

x%5E2%28a-b%29%2Ba%5E2%28b-x%29%2Bb%5E2%28x-a%29
a%5E2%28a-b%29%2Ba%5E2%28b-a%29%2Bb%5E2%28a-a%29
a%5E3-a%5E2b%2Ba%5E2b-a%5E3%2Bb%5E2%280%29
a%5E3-a%5E2b%2Ba%5E2b-a%5E3%2B0

and everything cancels out and we have

0

so 0 would be the remainder if 

x%5E2%28a-b%29%2Ba%5E2%28b-x%29%2Bb%5E2%28x-a%29

were divided by x-a, so 

x-a is a factor of  x%5E2%28a-b%29%2Ba%5E2%28b-x%29%2Bb%5E2%28x-a%29.

And of course x-a is linear because the highest power
of x is 1.

Edwin

Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
First, get rid of parens
x%5E2a-x%5E2b%2Ba%5E2b-a%5E2x%2Bb%5E2x-b%5E2a rearrange and regroup
%28a-b%29x%5E2-%28a%5E2-b%5E2%29x%2B%28a%5E2b-b%5E2a%29 expand %28a%5E2-b%5E2%29
%28a-b%29x%5E2-%28a-b%29%28a%2Bb%29x%2Bab%28a-b%29 factor out %28a-b%29
%28a-b%29%28x%5E2-%28a-b%29x%2Bab%29=
Since x%5E2-%28a-b%29x%2Bab equals %28x-a%29%28x-b%29, we have
%28a-b%29%28x-a%29%28x-b%29

Hope this helps---ptaylor