You can put this solution on YOUR website! Let's solve this system of equations using the elimination method.
First, we can multiply the two equations by necessary multiples such that the coefficients of y's in both equations are the same:
1. Multiply the first equation by 2 and the second equation by 3:
4x + 6y = 24 (Multiplying the first equation by 2)
3x - 6y = -9 (Multiplying the second equation by 3)
1. Add both equations to eliminate y:
(4x + 6y) + (3x - 6y) = 24 + (-9)
4x + 3x = 15
7x = 15
1. Divide by 7:
x = 15/7
1. Substitute the value of x into one of the original equations to find the value of y:
2x + 3y = 12
2(15/7) + 3y = 12
1. Solve for y:
3y = 12 - 30/7
3y = (84 - 30)/7
3y = 54/7
y = 18/7
So, the solution to the system is x = 15/7 and y = 18/7.
Really need help on this problem.
2x + 3y = 12
x - 2y = -3
Thank you in advance.
2x + 3y = 12 ------- eq (i)
x - 2y = -3 ------- eq (ii)
Id you so choose to use the ELIMINATION method to solve this system, then it's better to MANIPULATE eq (ii)
ONLY, unlike the approach the other person took. When manipulated (multiplied by 2), eq (ii) becomes:
2x - 4y = - 6 ----- eq (iii)
2x + 3y = 12 ----- eq (i)
7y = 18 ----- Subtracting eq (iii) from eq (i)
x - 2y = - 3 ------ Substituting for y in eq (ii)
