SOLUTION: find an equation for the line parallel to 3x+4y=12 that passes through the point (2,-5) ive already put it in y=mx+b form y=3/4x+3, but i have no idea what to do with the point (2

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Question 879438: find an equation for the line parallel to 3x+4y=12 that passes through the point (2,-5)
ive already put it in y=mx+b form y=3/4x+3, but i have no idea what to do with the point (2,-5)
thank you in advance
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi
3x+4y=12 |careful: hopping over the = with the 3x changes the sign of that term
('Hopping' is the same as Adding -3x to both sides of the Equation)
y =
m = -3/4
***Using point-slope form, P(2,-5)
y + 5 = (-3/4)(x - 2)
y = (-3/4)x + 3/2 - 5 (-5 = -10/2)
y = (-3/4)x - 7/2

Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

All you have done is attempt to put the original equation into slope-intercept form. Correctly done, you would have simply had another equation for the same line. Re-do the part you have done paying particular care with signs when solving for to get the correct slope intercept equation for your given line. Once you have done that, replace the constant term with a variable such a , and substitute the coordinates of the given point, that is 2 for and -5 for . That leaves you with a single variable equation in . Solve for and substitute back into your slope-intercept form equation to get the equation of the desired parallel.

John

My calculator said it, I believe it, that settles it