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Question 78305This question is from textbook
: The line through (0, -1) that is perpendicular to 2x - 5y = 10
This question is from textbook
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! The line through (0, -1) that is perpendicular to 2x - 5y = 10
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First find the slope by putting 2x - 5y = 10 in the slope/intercept form:
y = mx + b is the form we want
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2x - 5y = 10
-5y = -2x + 10
5y = 2x - 10; multiplied by -1 to make y positive
y = (2/5)x - 10/5; divided both sides by 5
y = (2/5)x - 2,
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The slope is 2/5; let m1 = 2/5
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The relationship of the slopes of perpendicular lines are: m1*m2 = -1
Find m2:
(2/5)*m2 = -1
m2 = -5/2 is the slope of the perpendicular line.
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Find the perpendicular line using the point/slope equation; y - y1 = m(x - x1)
Given that x1 = 0, y1 =-1; and we found m2 = -5/2
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y - (-1) = (-5/2)(x - 0)
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y + 1 = -(5/2)x
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y = -(5/2)x - 1; Subtract 1 from both sides, this is the perpendicular line
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