SOLUTION: determine the slope and y intercept of the problems:y=5x+3, y=-8x-1,y=4+2x,(8,4) and (2,1), (-9,8) and (10,- 4), (-1,-2) and (-3,-4)

Algebra ->  Linear-equations -> SOLUTION: determine the slope and y intercept of the problems:y=5x+3, y=-8x-1,y=4+2x,(8,4) and (2,1), (-9,8) and (10,- 4), (-1,-2) and (-3,-4)      Log On


   



Question 696105: determine the slope and y intercept of the problems:y=5x+3, y=-8x-1,y=4+2x,(8,4) and (2,1), (-9,8) and (10,- 4), (-1,-2) and (-3,-4)
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If you have the equation for a line in the form y=mx%2Bb,
called the highlight%28slope-intercept%29 form
(or if you can transform the equation you have into that form),
the numbers m and b are the slope and y-intercept respectively.
For y=5x%2B3 , highlight%28slope=5%29 and highlight%28y-intercept=3%29
For y=-8x-1 , highlight%28slope=-8%29 and highlight%28y-intercept=-1%29
For y=4%2B2x<-->y=2x%2B4 , highlight%28slope=2%29 and highlight%28y-intercept=4%29

If you have two points, you can determine the slope and, the y-intercept, and the equation of the line.
I see two simple ways about it:
solve it as a system of equations,
or use what you learned about analytical geometry.
The choice of method depends on your preference (what is easier for you) and your teacher's preference.

USING SYSTEMS OF EQUATIONS:
For the line that passes through (8,4) and (2,1),
substituting x=8 and y=4 (coordinates of (8,4)) into y=mx%2Bb we get
4=8m%2Bb
Doing the same with point (2,1), we get
1=2m%2Bb
That gives you the system system%284=8m%2Bb%2C2x%2Bb%29
that you can solve for m and b.
Subtracting the second equation from the first, you get
3=6m --> m=3%2F6=1%2F2 so highlight%28slope=1%2F2%29
Substituting that value into 1=2m%2Bb , you get
1=2%281%2F2%29%2Bb --> 1=1%2Bb --> b=0 so highlight%28y-intercept=0%29

USING ANALYTICAL GEOMETRY:
The slope of a line is defined as the ratio between the increase in y-coordinate and the increase in x-coordinate when going from one point to the other.
That is easier to write in words than as the usual cumbersome formula, which looks like
slope=highlight%28m=%28y%5B1%5D-y%5B2%5D%29%2F%28x%5B1%5D-x%5B2%5D%29%29
for known points P%5B1%5D (x%5B1%5D,y%5B1%5D) and P%5B1%5D (x%5B1%5D,y%5B1%5D).
Then, for any point (x,y) on the line, and a known point (x%5BA%5D,y%5BA%5D)
m=%28y-y%5BA%5D%29%2F%28x-x%5BA%5D%29 --> highlight%28y-y%5BA%5D=m%28x-x%5BA%5D%29%29
gives the equation of the line in the highlight%28point-slope%29 form,
which can be transformed into the highlight%28slope-intercept%29 form.

For the line that passes through (8,4) and (2,1),
so as not to get all those numbers mixed up,
you could write into the formula the coordinates of one point at a time.
You may start with point (8,4), with x=8 and y=4, and write
slope=%284-y%5B2%5D%29%2F%288-x%5B2%5D%29 (leaving the spaces for x%5B2%5D and y%5B2%5D blank).
Then, you could fill in the coordinates of the other point to get
slope=%284-1%29%2F%288-2%29=3%2F6=1%2F2 so highlight%28slope=1%2F2%29
Then you can write the equation of the line in point-slope form,
maybe using point (2,1) as your point:
y-1=%281%2F2%29%28x-2%29
That can be transformed int the slope intercept form:
y-1=%281%2F2%29%28x-2%29-->y-1=%281%2F2%29x-1%29-->highlight%28%281%2F2%29x%29
The y-intercept is that invisible 0 added after the %281%2F2%29x
so highlight%28y-intercept=0%29.

For the line that passes through (-9,8) and (10,- 4)
Slope=%288-%28-4%29%29%2F%28-9-10%29=12%2F%28-19%29=highlight%28-12%2F19%29
y-%28-4%29=%28-12%2F19%29%28x-10%29-->y%2B4=%28-12%2F19%29x%2B120%2F19-->y=%28-12%2F19%29x%2B120%2F19-4-->y=%28-12%2F19%29x%2B120%2F19-76%2F19-->y=%28-12%2F19%29x%2B44%2F19
So highlight%28y-intercept=44%2F19%29.

For the line that passes through (-1,-2) and (-3,-4)
Slope=%28-2-%28-4%29%29%2F%28-1-%28-3%29%29=%28-2%2B4%29%2F%28-1%2B3%29=2%2F2=highlight%281%29
y-%28-4%29=1%28x-%28-3%29%29-->y%2B4=x%2B3-->y=x%2B3-4-->y=x-1
So highlight%28y-intercept=-1%29.