Question 37611: Find the slope of the sides of rectangle ABCD having vertices A=(1,4) and
B=(-5,3). Found 2 solutions by venugopalramana, josmiceli:Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! Find the slope of the sides of rectangle ABCD having vertices A=(1,4)=(X1,Y1) and
B=(-5,3)=(X2,Y2)
SLOPE OF AB =(Y2-Y1)/(X2-X1)=(3-4)/(-5-1)=-1/-6=1/6
IN A RECTANGLE OPPOSITE SIDES ARE PARALLEL AND ADJACENT SIDES ARE PERPENDICULAR.HENCE
SLOPE OF CD=1/6
SLOPE BC=SLOPE OF AD =-1/(1/6)=-6
You can put this solution on YOUR website! You don't have to get into the size of the rectangle or where the other 2 vertices are located. All you need to know is that 2 sides are parallel and the other 2
sides are perpendicular to them.
P = (x,y)
P(1) = (-5,3)
P(2) = (1,4) where m = slope
the slope perpendicular to this is
the graph is of point (-5,3) with the perpendicular sides going through the point
