|
Question 368095: My question:
graph each line using slope-intercept form
5-y=3/4x
This is how far I got:
5-y=3/4x
-5 -5
-y=3/4x-5
now this is where im stumped, how do i get rid of the negative on the y?
Found 2 solutions by stanbon, nyc_function:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! graph each line using slope-intercept form
5-y=3/4x
This is how far I got:
5-y=3/4x
-5 -5
-y=3/4x-5
now this is where im stumped, how do i get rid of the negative on the y?
-----
Multiply both sides of the equation by -1 to get:
y = (-3/4)x + 5
---
Graph:
Let x = 0, then y = 5
Let x = 4, then y = 2
Plot (0,5) and (4,2) and draw a line thru them to get:
===============
Cheers,
Stan H.
Answer by nyc_function(2741)  (Show Source):
You can put this solution on YOUR website! Nice work! Now divide every term by -1.
Where is -1? It is indicated by the negative in front of y.
In other words, -y means -1 times y.
The same is true for any variable. If there is a negative sign in front of a variable, it is considered to be -1 times the variable.
Back to your question.
-y = (3/4)x - 5
y = (-3/4)x + 5
Copy and paste the link below to see your graph.
http://mathway.com/answer.aspx?p=grap?p=ySMB01(-3SMB104)x+5?p=False?p=False?p=True?p=False?p=True
|
|
|
| |
