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Question 233514: I have a story problem
The representative tells you that floor plan #1 sells for $175,000 and floor plan #2 sells for $200,000 She also mentions that all the available houses combined are worth $7,200,000. Write an equation that eliminates the situation, using x an y as your variables.
Then uses elimination method to determine how many houses with each floor plan are available.
Thank you for your immediate response
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I have a story problem
The representative tells you that floor plan #1 sells for $175,000 and floor plan #2 sells for $200,000.
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She also mentions that all the available houses combined are worth $7,200,000.
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Write an equation that eliminates the situation, using x an y as your variables. Then use elimination method to determine how many houses with each floor plan are available.
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Let x be the # of 175000 homes
Let y be the # of 200000 homes
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Quantity Equation: x + y = 38
Value: 175000x + 200000y = 7,200,000
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Muliply thru the Quantity equation by 175000 to get:
175000x + 175000y = 38(175000)
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Subtract that from the Value equation and solve for "y":
25000y = 550000
y = 22 (# of $200,000 homes available)
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Since x + y = 38, x = 38-22 = 16 (# of #175,000 homes available)
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Comment: You have to post the total number of houses or
some other information relating the two floorplan
quantities.
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Cheers,
Stan H.
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