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Question 225949: Could you help me with this problem please?
Find the area of a triangle formed by the x-axis, the line y=-6x+60, and the line 3x-4y=-24.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the area of a triangle formed by the x-axis, the line y=-6x+60, and the line 3x-4y=-24.
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Find where the 2 lines intersect.
y = -6x+60
3x-4y = -24
Sub for y in 2nd eqn
3x - 4(-6x+60) = -24
3x + 24x-240 = -24
27x = 216
x = 8
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y = -6x+60 = 12
--> (8,12)
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Find the x-intercepts of the 2 lines by setting y=0.
y = -6x+60
0 = -6x+60
x = 10
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3x-4y = -24
3x = -24
x = -8
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The base of the triangle is from x = -8 to x = 10, = 18 units.
The height is the y value of the intersection, = 12
Area = b*h/2 = 18*12/2
Area = 108 sq units.
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