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Question 173425: Find the equation of a perpendicular line 2x+5y=1 containing points (-1,2)
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the equation of a perpendicular line 2x+5y=1 containing points (-1,2)
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Find the slope, m, of line 2x+5y=1 by putting it into slope-intercept form.
2x+5y=1
5y = -2x + 1
y = (-2/5)x + 1/5
m = -2/5. Lines perpendicular to it will have the negative inverse slope, +5/2
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y-y1 = m*(x-x1) where (x1,y1) is the point (-1,2)
y - 2 = (5/2)*(x + 1)
y-2 = (5/2)x + 5/2
y = (5/2)x + 9/2 slope-intercept form
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2y = 5x + 9
5x - 2y = -9 standard form
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