|
Question 154642: A straight line passes through the point (4,3) and is perpendicular to the line joining the points (-1,3) and (1,-1). Find the equation of this line.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A straight line passes through the point (4,3) and is perpendicular to the line joining the points (-1,3) and (1,-1). Find the equation of this line.
-------------------
Find the slope of the line thru the 2 points:
m1 = (y2 - y1)/(x2 - x1)
m1 = (-1 -3)/(1 -(-1))
m1 = -4/2 = -2
To be perpendicular, the slope m2 is the negative inverse of m1, -1/m1
m2 = 1/2
Use (x3,y3) = (4,3)
y - y3 = m2*(x - x3)
y - 3 = (1/2)*(x - 4)
2y - 6 = x - 4
x - 2y = -2
|
|
|
| |
