SOLUTION: What is the equation of the line passing through (-3, 7) and perpendicular to -7x-8y=77?

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Question 132228This question is from textbook
: What is the equation of the line passing through (-3, 7) and perpendicular to -7x-8y=77? This question is from textbook

Answer by solver91311(24713) About Me  (Show Source):
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Lines are perpendicular if and only if their slopes are negative reciprocals of each other. If m%5B1%5D is the slope of one of the lines and m%5B2%5D is the slope of the other line, then they are perpendicular if m%5B1%5D=-1%2Fm%5B2%5D.

Start with the equation of the given line and put it into slope-intercept form (y=mx%2Bb) by solving for y:

-7x-8y=77

-8y=7x%2B77

y=-7x%2F8-77%2F8

Therefore the slope of the given line is -7%2F8 because that is the coefficient on x when the equation is in slope-intercept form.

Since you want to derive the equation for a line perpendicular to the given line, you need the negative reciprocal of the slope of the given line, so:

-1%2F%28-7%2F8%29=8%2F7

Now that you have the slope determined and you are given a point, you can use the point-slope form to derive the equation of the desired perpendicular.

Point-slope form: y-y%5B1%5D=m%28x-x%5B1%5D%29 where (x%5B1%5D,y%5B1%5D) are the co-ordinates of the given point and m is the slope.

y-7=%288%2F7%29%28x-%28-3%29%29, is an equation for the desired line. However, you probably want to put it into standard form just like the given equation at the start.

y-7=%288%2F7%29%28x%2B3%29

Multiply by 7
7y-49=8x%2B24

-8x%2B7y=24%2B49

-8x%2B7y=73