SOLUTION: A group of friends decides to go out of town to a championship football game. The group pays $185 per ticket plus a one-time convenience fee of $15. They also pay $27 to ride a tou

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Question 1204350: A group of friends decides to go out of town to a championship football game. The group pays $185 per ticket plus a one-time convenience fee of $15. They also pay $27 to ride a tour bus to the game. If the group spent $2,771 in total, how many friends are in the group?

Found 3 solutions by math_tutor2020, ikleyn, greenestamps:
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

n = number of people

The equation to solve is
185n + 15 + 27 = 2771

The unfortunate thing is that the solution is n = 2729/185 = 14.751 approximately
It's not possible to have a fractional number of people. It's possible that your teacher made a typo.

Edit: if the $27 refers to the cost per person to ride the bus, then the equation would be 185n + 15 + 27n = 2771 which solves to n = 13

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.

The solution is in one line


    %282771-15%29%2F%28185%2B27%29 = 13 friends in the group.

Solved.

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Surely, the problem is formulated incorrectly, leaving to a reader to guess
what $27 are - one time payment or a payment for each person of a group.

Math problems are NEVER presented/formulated this way.

Only totally   highlight%28highlight%28incompetent%29%29   people formulate problems this way as it is done in this post -
- those who do not distinct a Math problem from a third-rate puzzle.



Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The problem is clearly stated incorrectly.

As the problem is given, $27 is the cost of the tour bus -- not the cost per person of the tour bus.

But to get a whole number answer for the number of friends in the group, you have to use $27 as the cost per person for the tour bus.

So the response from tutor @Math_Tutor2020 is the correct response for the problem as stated.