SOLUTION: Prove that the points A(-2,-3), B(6,2), C(8,7) and D(0,2) are the vertices of a parallelogram.

Algebra ->  Linear-equations -> SOLUTION: Prove that the points A(-2,-3), B(6,2), C(8,7) and D(0,2) are the vertices of a parallelogram.      Log On


   

Question 1129802: Prove that the points A(-2,-3), B(6,2), C(8,7) and D(0,2) are the vertices of a parallelogram.
Answer by math_helper(2461) About Me  (Show Source):
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Slope of AB: (2-(-3)) / (6-(-2)) = 5/8
Slope of CD: (2-7) / (0 - 8) = -5/-8 = 5/8

So AB is parallel to CD


Slope of AD: (2-(-3)) / (0-(-2)) = 5/2
Slope of BC: (7-2) / (8-6) = 5/2
So AD is parellel to BC

Since AB || CD and AD || BC, ABCD forms a parallelogram. ∎