SOLUTION: find the coordinates of the vertices of a triangle whose sides lie on the following three lines 2x+5y-16=0, 4x-3y-6=0, 3x+y+2=0
Algebra ->
Length-and-distance
-> SOLUTION: find the coordinates of the vertices of a triangle whose sides lie on the following three lines 2x+5y-16=0, 4x-3y-6=0, 3x+y+2=0
Log On
Question 219404: find the coordinates of the vertices of a triangle whose sides lie on the following three lines 2x+5y-16=0, 4x-3y-6=0, 3x+y+2=0 Answer by susanaramya(12) (Show Source):
You can put this solution on YOUR website! The coordinates of the point joining line 2x+5y=16 and 4x-3y=6
2x+5y=16 -------------(1)
4x-3y=6 -------------(2)
(1)*2=> 4x+10y=32-----(3)
(2) => 4x-3y= 6------(4)
(3)-(4)=>13y=26 or y=2
substituting in (1) 2x+5*2=16
2x+10=16
2x=6 or x=3
(x,y)=(3,2)
The coordinates of the point joining line 4x-3y=6 and 3x-y=-2
4x-3y=6--------------(1)
3x-y=-2--------------(2)
(