SOLUTION: You need a 40% alcohol solution. On hand, you have a 160 mL of a 50% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
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Question 1162873: You need a 40% alcohol solution. On hand, you have a 160 mL of a 50% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
You will need
__ mL of pure water to obtain
__ mL of the desired 40% solution. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 160 ml*0.50 alcohol is 80 ml pure alcohol wanted in final solution
add x ml water
now have (160+x)*(0.40)=80 ml pure alcohol
64+0.40x=80
0.40x=16 ml
x=40 ml of water ANSWER
that will give 200 ml of solution of 40% or 80 ml pure alcohol. ANSWER
