SOLUTION: You need a 35% alcohol solution. On hand, you have a 140 mL of a 65% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
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Question 1162819: You need a 35% alcohol solution. On hand, you have a 140 mL of a 65% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
You will need _____ mL of pure water to obtain ______mL of the desired 35% solution. Found 3 solutions by ikleyn, MathTherapy, Alan3354:Answer by ikleyn(52799) (Show Source):
Let x be the volume of the pure water under the question, in mL.
Then the volume of the pure alcohol in 140 mL of the 65% alcohol solution is 0.65*140 mL.
The total volume after adding x mL of water is (140+x) mL.
The concentration equation for the resulting mixture after adding water is
= 0.35.
From the equation,
0.065*140 = 0.35*(140+x)
0.065*140 = 0.35*140 + 0.35x
x = = 120 mL.
ANSWER. 120 mL of water should be added.
You can put this solution on YOUR website!
You need a 35% alcohol solution. On hand, you have a 140 mL of a 65% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
You will need _____ mL of pure water to obtain ______mL of the desired 35% solution.
Let amount of water to add be W
Percent of water in 65% mixture: 35
Required percent of water in 35% mixture: 65
We then get following: .35(140) + W = .65(140 + W)
49 + W = 91 + .65W
.35W = 42
Amount of water to add, or
You can put this solution on YOUR website! You will need _____ mL of pure water to obtain ______mL of the desired 35% solution.
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