SOLUTION: How do I find the slope of a line perpendicular (8,12)(3.9)

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Question 684323: How do I find the slope of a line perpendicular (8,12)(3.9)
Found 2 solutions by ReadingBoosters, MathLover1:
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
First find slope using (8, 12) and (3, 9)
%2812-9%29%2F%288-3%29+=+3%2F5
...
A perpendicular line will have a negative inverse/reciprocal slope of highlight_green%28-5%2F3%29
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Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
first find a line that passes through given point (8,12)and has slope m=3.9
Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (8, 12)

  • it has a slope of 3.9



First, let's draw a diagram of the coordinate system with point (8, 12) plotted with a little blue dot:



Write this down: the formula for the equation, given point x%5B1%5D%2C+y%5B1%5D and intercept a, is

y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29 (see a paragraph below explaining why this formula is correct)

Given that a=3.9, and system%28+x%5B1%5D+=+8%2C+y%5B1%5D+=+12+%29+, we have the equation of the line:

y=3.9%2Ax+%2B+-19.2

Explanation: Why did we use formula y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29 ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (x%5B1%5D, y%5B1%5D) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (x%5B1%5D, y%5B1%5D): y%5B1%5D+=+a%2Ax%5B1%5D%2Bb Here, we know a, x%5B1%5D, and y%5B1%5D, and do not know b. It is easy to find out: b=y%5B1%5D-a%2Ax%5B1%5D. So, then, the equation of the line is: +y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+.

Here's the graph:




now we can find the slope of a line perpendicular to a line y=3.9x-19.2 which passes through given points
perpendicular line has a slope -1%2F3.9=-0.26

Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (8, 12)

  • it has a slope of -0.26



First, let's draw a diagram of the coordinate system with point (8, 12) plotted with a little blue dot:



Write this down: the formula for the equation, given point x%5B1%5D%2C+y%5B1%5D and intercept a, is

y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29 (see a paragraph below explaining why this formula is correct)

Given that a=-0.26, and system%28+x%5B1%5D+=+8%2C+y%5B1%5D+=+12+%29+, we have the equation of the line:

y=-0.26%2Ax+%2B+14.08

Explanation: Why did we use formula y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29 ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (x%5B1%5D, y%5B1%5D) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (x%5B1%5D, y%5B1%5D): y%5B1%5D+=+a%2Ax%5B1%5D%2Bb Here, we know a, x%5B1%5D, and y%5B1%5D, and do not know b. It is easy to find out: b=y%5B1%5D-a%2Ax%5B1%5D. So, then, the equation of the line is: +y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+.

Here's the graph:





y=-0.26x-14.08

+graph%28+600%2C+600%2C+-10%2C+10%2C+-30%2C+10%2C+3.9x-19.2%2C+-0.26x-14.08%29+