SOLUTION: I am trying to solve the below problem but I have question.
-7(5y – 2) > 6(6y-1)
I first multiplied
-35y- -14> 36y-6
Then added 6 to both sides
-35y- -14+6>36y -6+6
Algebra ->
Inequalities
-> SOLUTION: I am trying to solve the below problem but I have question.
-7(5y – 2) > 6(6y-1)
I first multiplied
-35y- -14> 36y-6
Then added 6 to both sides
-35y- -14+6>36y -6+6
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Question 349087: I am trying to solve the below problem but I have question.
-7(5y – 2) > 6(6y-1)
I first multiplied
-35y- -14> 36y-6
Then added 6 to both sides
-35y- -14+6>36y -6+6
-35y- -8>36y
I am confused, I am not sure if the next step is correct.
You can put this solution on YOUR website! I am trying to solve the below problem but I have question.
-7(5y – 2) > 6(6y-1)
I first multiplied
-35y- -14> 36y-6
Now this should be
-35y + 14 > 36y - 6
Then added 6 to both sides
-35y + 14 + 6 > 36y
-35y + 20 > 36y
Subtract 20 from both sides
-35y - 36y > -20
-71y > -20
y has to be positive, multiply both sides by -1, this reverses the inequality sign
71y < 20
y = <