SOLUTION: How would you solve following inequality? |2x-3|>5

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Question 312490: How would you solve following inequality?
|2x-3|>5

Found 3 solutions by rapaljer, Fombitz, Edwin McCravy:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
First, I would recognize that since this is an ABSOLUTE VALUE problem that ais GREATER THAN a positive number, this is an EXTREMES problem. It has two categories of solutions:

First solutions:
2x-3 > 5
2x >8
x>4

Second solutions:
2x-3 < -5
2x <-2
x<-1

In interval notation, this would be (-inf, -1) U (4, inf).

Dr. Robert J. Rapalje, Retired

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Two solutions:
%282x-3%29%3E5 and -%282x-3%29%3E5
Positive solution:
2x-3%3E5
2x%3E8
highlight_green%28x%3E4%29
.
.
.
Negative solution:
-%282x-3%29%3E5
2x-3%3C-5
2x%3C-2
highlight_green%28x%3C-1%29
The solution set is (-infinity,-1)U(4,infinity).
.
.
.
Verified graphically,
+graph%28+300%2C+300%2C+-4%2C+6%2C+-10%2C+10%2C+abs%282x-3%29%2C+5%29+

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!


|2x - 3| > 5 

That says 2x - 3 is either less than -5 or else it's greater than +5, 
but not inclusive of either -10 or +10 since the symbol
of inequality is > and not >

And that is the same thing as saying:

2x - 3 < -5 OR 2x - 3 > +5 

Add 3 to both sides in both inequalities to get 2x alone 
on the left of each one

2x - 3 < -5 OR 2x - 3 > +5
   + 3   +3       + 3   +3
---------------------------
2x     < -2 OR 2x    >   8 

Divide both sides of both inequalities by 2 to solve for x 
in each one:

  2x%2F2 < %28-2%29%2F2 OR  < 2x%2F2 > 8%2F2

x < -1  OR  x > 4 

on a number line that has this graph:

<========================o-------------------o====================>
-7  -6  -5  -4  -3  -2  -1   0   1   2   3   4   5   6   7   8   9  

In interval notation, that's (-infinity, -1) U (4, infinity)

Edwin