SOLUTION: square root(7)< x < square root(37)and x is an integer, then x can have how many different values? a 3 b 4 c 5 d 8

Algebra ->  Inequalities -> SOLUTION: square root(7)< x < square root(37)and x is an integer, then x can have how many different values? a 3 b 4 c 5 d 8       Log On


   



Question 277459: square root(7)< x < square root(37)and x is an integer, then x can have how many different values?
a 3 b 4 c 5 d 8

Found 2 solutions by JBarnum, Alan3354:
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
well the sqrt%287%29=2.64 and thesqrt%2837%29=6.08
so the only whole integers between them are 3,4,5,6. so there are 4 possible values

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
square root(7)< x < square root(37)and x is an integer, then x can have how many different values?
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sqrt(7) = -2.645...
--> -2, -1, 0, 1, 2, 3, 4, 5, 6
= 9 integer values
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The final answer is: This is a poorly worded problem. The author did not take into account all the possibilities.
It's all too common. The people that write the textbooks don't go outside and have little contact with reality.