SOLUTION: (To whomsoever sees this your help would be greatly appreciated) Solve the absolute value inequality |7x-3|≤18

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Question 1180733: (To whomsoever sees this your help would be greatly appreciated)
Solve the absolute value inequality
|7x-3|≤18
Found 3 solutions by josgarithmetic, greenestamps, ikleyn:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
If 7x-3 positive then 7x-3%3C=18
7x%3C=21
x%3C=3

If 7x-3 not positive then -%287x-3%29%3C=18
-7x%2B3%3C=18
-7x%3C=15
x%3E=-15%2F7

highlight%28-15%2F7%3C=x%3C=3%29

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


abs%287x-3%29%3C=18

The absolute value of the expression is less than or equal to 18, so the value of the expression is greater than or equal to -18 and less than or equal to +18:

-18%3C=7x-3%3C=18

Add 3 to all three parts of the compound inequality to get the term with x by itself:

-15%3C=7x%3C=21

Divide all three parts by 7 to solve for x alone:

-15%2F7%3C=x%3C=3

Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.

I just solved it and answered under this link

https://www.algebra.com/algebra/homework/Inequalities/Inequalities.faq.question.1180732.html

https://www.algebra.com/algebra/homework/Inequalities/Inequalities.faq.question.1180732.html


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