Question 1069494: (SinŲ-cosŲ+1)÷(sinŲ+cosŲ-1)=secŲ+tanŲ
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! multiply numerator and denominator by conjugate of denominator, (sin x + cos x+1)
The numerator becomes sin^2 x+ 2 sin x - cos ^2x+1, but cos^2x=1-sin ^2 x,
making the numerator 2sin^2 x+ 2 sin x
The denominator becomes 2 sin x*cos x
All the 2 divide out
fractions are
{sin^2 x/sin x* cos x} + {sin x/sin x* cos x}
This is (sin x/cos x) + (1/cos x)
or sin x/ cos x = tan x
(1/cos x)= sec x
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