Question 1200133: -An experimental surgical procedure is being studied as an alternative to the existing method. Twelve surgeons perform the operation on two different patients matched by sex, age and other relevant factors.
Problem Definition: Determine whether or not the new procedure is faster than the existing procedure. Alpha is .05
I NEED HELP WITH THIS STEP BELOW. I PUT ALL THE DATA INTO MINITAB AND CAME UP WITH THE STATISTICS BUT I'M NOT SURE BOW TO INTERPRET IT:
-Utilize all three techniches: critical value technique, the confidence interval and the p-value in your conclusion. Include the numbers from the minitab output for each technique. Write your assumption and discuss how you know whether or not normality may be assumed.
Descriptive Statistics:
Sample N Mean StDev SE Mean
New Procedure 12 13.25 2.38 0.69
Old Procedure 12 23.42 3.58 1.03
Estimation for Paired Difference:
Mean StDev SE Mean 95% Upper Bound
for μ_difference
-10.17 3.83 1.11 -8.18
µ_difference: population mean of (New Procedure - Old Procedure)
Test:
Null hypothesis H₀: μ_difference = 0
Alternative hypothesis H₁: μ_difference < 0
T-Value P-Value
-9.19 0.000
Answer by math_tutor2020(3817)   (Show Source):
You can put this solution on YOUR website!
The Minitab output you copy/pasted doesn't appear to be fully coherent.
The critical value and confidence interval information is either missing, or garbled in the table.
However, the p-value appears to be intact.
A p-value of 0.000 means it's so small that it's practically zero.
Since the p-value is smaller than alpha = 0.05, we reject the null. A handy phrase could be "If the p-value is low, then the null must go".
So we go with
Alternative hypothesis H1: μ_difference < 0
and conclude that the new experimental surgical procedure appears to be faster than the existing procedure.
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