Question 116227: Paul is five times as old as his daughter Anna. In 12 years, Paul will be three times as old as Anna is in twelve years. How old is each one now?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Write an expression or equation for each statement:
P = Paul's age now; A = Anna's age now
:
"Paul is five times as old as his daughter Anna. "
P = 5A
:
In 12 yrs, their ages will be:
P+12
and
A+12
:
"In 12 years, Paul will be three times as old as Anna is in twelve years."
P + 12 = 3(A + 12)
P + 12 = 3A + 36
P = 3A + 36 - 12
P = 3A + 24
:
How old is each one now?
From the 1st statement; P = 5A; replace P with 5A and solve for A
5A = 3A + 24
5A - 3A = 24
2A = 24
A = 24/2
A = 12 yrs now, obviously Paul: 5 * 12 = 60 yrs now
:
:
Check our solution using the statement:
"In 12 years, Paul will be three times as old as Anna is in twelve years. "
(60 + 12) = 3(12 + 12)
72 = 3(24)
:
Hopefully, this method will simplify things for you.
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