SOLUTION:
John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of
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John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of
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Question 72919:
John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.
Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained. Use the vertex formula to find the maximum area.
You can put this solution on YOUR website! THE MAXIMUM AREA FOR ANY RECTANGLE IS A SQUARE. THUS:
4X=300
X=300/4
X=75 LENGTH OF THE SIDES
THEREFORE THE AREA IS
75^2=5625 SQ FEET
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